Optimal. Leaf size=106 \[ \frac {7 (1-2 x)^{3/2}}{3 (3 x+2) (5 x+3)}-\frac {748 \sqrt {1-2 x}}{15 (5 x+3)}-\frac {910}{3} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )+\frac {1562}{5} \sqrt {\frac {11}{5}} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right ) \]
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Rubi [A] time = 0.03, antiderivative size = 106, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {98, 149, 156, 63, 206} \begin {gather*} \frac {7 (1-2 x)^{3/2}}{3 (3 x+2) (5 x+3)}-\frac {748 \sqrt {1-2 x}}{15 (5 x+3)}-\frac {910}{3} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )+\frac {1562}{5} \sqrt {\frac {11}{5}} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right ) \end {gather*}
Antiderivative was successfully verified.
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Rule 63
Rule 98
Rule 149
Rule 156
Rule 206
Rubi steps
\begin {align*} \int \frac {(1-2 x)^{5/2}}{(2+3 x)^2 (3+5 x)^2} \, dx &=\frac {7 (1-2 x)^{3/2}}{3 (2+3 x) (3+5 x)}+\frac {1}{3} \int \frac {(131-31 x) \sqrt {1-2 x}}{(2+3 x) (3+5 x)^2} \, dx\\ &=-\frac {748 \sqrt {1-2 x}}{15 (3+5 x)}+\frac {7 (1-2 x)^{3/2}}{3 (2+3 x) (3+5 x)}+\frac {1}{15} \int \frac {-3771+2306 x}{\sqrt {1-2 x} (2+3 x) (3+5 x)} \, dx\\ &=-\frac {748 \sqrt {1-2 x}}{15 (3+5 x)}+\frac {7 (1-2 x)^{3/2}}{3 (2+3 x) (3+5 x)}+\frac {3185}{3} \int \frac {1}{\sqrt {1-2 x} (2+3 x)} \, dx-\frac {8591}{5} \int \frac {1}{\sqrt {1-2 x} (3+5 x)} \, dx\\ &=-\frac {748 \sqrt {1-2 x}}{15 (3+5 x)}+\frac {7 (1-2 x)^{3/2}}{3 (2+3 x) (3+5 x)}-\frac {3185}{3} \operatorname {Subst}\left (\int \frac {1}{\frac {7}{2}-\frac {3 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )+\frac {8591}{5} \operatorname {Subst}\left (\int \frac {1}{\frac {11}{2}-\frac {5 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )\\ &=-\frac {748 \sqrt {1-2 x}}{15 (3+5 x)}+\frac {7 (1-2 x)^{3/2}}{3 (2+3 x) (3+5 x)}-\frac {910}{3} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )+\frac {1562}{5} \sqrt {\frac {11}{5}} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )\\ \end {align*}
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Mathematica [A] time = 0.08, size = 105, normalized size = 0.99 \begin {gather*} \frac {-22750 \sqrt {21} \left (15 x^2+19 x+6\right ) \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )+14058 \sqrt {55} \left (15 x^2+19 x+6\right ) \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right )-15 \sqrt {1-2 x} (2314 x+1461)}{225 (3 x+2) (5 x+3)} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.24, size = 101, normalized size = 0.95 \begin {gather*} \frac {4 \sqrt {1-2 x} (1157 (1-2 x)-2618)}{15 \left (15 (1-2 x)^2-68 (1-2 x)+77\right )}-\frac {910}{3} \sqrt {\frac {7}{3}} \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )+\frac {1562}{5} \sqrt {\frac {11}{5}} \tanh ^{-1}\left (\sqrt {\frac {5}{11}} \sqrt {1-2 x}\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 1.57, size = 122, normalized size = 1.15 \begin {gather*} \frac {7029 \, \sqrt {11} \sqrt {5} {\left (15 \, x^{2} + 19 \, x + 6\right )} \log \left (-\frac {\sqrt {11} \sqrt {5} \sqrt {-2 \, x + 1} - 5 \, x + 8}{5 \, x + 3}\right ) + 11375 \, \sqrt {7} \sqrt {3} {\left (15 \, x^{2} + 19 \, x + 6\right )} \log \left (\frac {\sqrt {7} \sqrt {3} \sqrt {-2 \, x + 1} + 3 \, x - 5}{3 \, x + 2}\right ) - 15 \, {\left (2314 \, x + 1461\right )} \sqrt {-2 \, x + 1}}{225 \, {\left (15 \, x^{2} + 19 \, x + 6\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 1.00, size = 116, normalized size = 1.09 \begin {gather*} -\frac {781}{25} \, \sqrt {55} \log \left (\frac {{\left | -2 \, \sqrt {55} + 10 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {55} + 5 \, \sqrt {-2 \, x + 1}\right )}}\right ) + \frac {455}{9} \, \sqrt {21} \log \left (\frac {{\left | -2 \, \sqrt {21} + 6 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}\right )}}\right ) + \frac {4 \, {\left (1157 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - 2618 \, \sqrt {-2 \, x + 1}\right )}}{15 \, {\left (15 \, {\left (2 \, x - 1\right )}^{2} + 136 \, x + 9\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.02, size = 70, normalized size = 0.66 \begin {gather*} -\frac {910 \sqrt {21}\, \arctanh \left (\frac {\sqrt {21}\, \sqrt {-2 x +1}}{7}\right )}{9}+\frac {1562 \sqrt {55}\, \arctanh \left (\frac {\sqrt {55}\, \sqrt {-2 x +1}}{11}\right )}{25}+\frac {242 \sqrt {-2 x +1}}{25 \left (-2 x -\frac {6}{5}\right )}+\frac {98 \sqrt {-2 x +1}}{9 \left (-2 x -\frac {4}{3}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.28, size = 110, normalized size = 1.04 \begin {gather*} -\frac {781}{25} \, \sqrt {55} \log \left (-\frac {\sqrt {55} - 5 \, \sqrt {-2 \, x + 1}}{\sqrt {55} + 5 \, \sqrt {-2 \, x + 1}}\right ) + \frac {455}{9} \, \sqrt {21} \log \left (-\frac {\sqrt {21} - 3 \, \sqrt {-2 \, x + 1}}{\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}}\right ) + \frac {4 \, {\left (1157 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} - 2618 \, \sqrt {-2 \, x + 1}\right )}}{15 \, {\left (15 \, {\left (2 \, x - 1\right )}^{2} + 136 \, x + 9\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.10, size = 72, normalized size = 0.68 \begin {gather*} \frac {1562\,\sqrt {55}\,\mathrm {atanh}\left (\frac {\sqrt {55}\,\sqrt {1-2\,x}}{11}\right )}{25}-\frac {910\,\sqrt {21}\,\mathrm {atanh}\left (\frac {\sqrt {21}\,\sqrt {1-2\,x}}{7}\right )}{9}-\frac {\frac {10472\,\sqrt {1-2\,x}}{225}-\frac {4628\,{\left (1-2\,x\right )}^{3/2}}{225}}{\frac {136\,x}{15}+{\left (2\,x-1\right )}^2+\frac {3}{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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